Loop Exercise 1

On this page, you will see some loop exercise and their solution.

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Exercise 1:

Write a program (WAP) that will print following series upto N^th terms.
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, ……,N.

Solution:

    #include<stdio.h>
    int main(){
    int n;
    scanf("%d",&n);
    for(int i=1;i<=n;i++){
        if(i==n){
            printf("%d",i);
        }
        else{
            printf("%d, ",i);
        }
    }
    return 0;
    }

Output:

  5
  1, 2, 3, 4, 5

Exercise 2:

Write a program (WAP) that will print following series upto N^th terms.
1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31 ……N.

Solution:

    #include<stdio.h>
    int main(){
    int n, value=1;
    scanf("%d",&n);
    for(int i=1;i<=n;i++){
      if(i==n){
        printf("%d",value);
      }
      else{
        printf("%d, ",value);
      }
      value+=2;
    }
    return 0;
    }

Output:

    11
    1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21

Exercise 3:

Write a program (WAP) that will print following series upto N^th terms.
1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, …… N.

Solution:

    #include<stdio.h>
    int main(){
    int n;
    scanf("%d",&n);
    for(int i=1;i<=n;i++){
      if(i%2!=0){
        if(i==n){
           printf("1");  
        }
        else{
           printf("1, ");  
        }    
      }
      else{
        if(i==n){
          printf("0");  
        }
        else{
          printf("0, ");  
        }
      }
    }
    return 0;
    }

Output:

    13
    1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1

Exercise 4:

Write a program (WAP) that will take N numbers as inputs and compute their average.
[N:B: Restriction: Without using any array ]

Solution:

    #include<stdio.h>
    int main(){
    int n;
    scanf("%d",&n);
    float total,num;
    for(int i=1;i<=n;i++){
      scanf("%f",&num);
      total+=num;
    }
    printf("AVG of %d inputs: %f",n,(total/n));
    return 0;
    }

Output:

    3
    10 20 30.5
    AVG of 3 inputs: 20.166666  

Exercise 5:

Write a program (WAP) that will take two numbers X and Y as inputs. Then it will print the square of X and increment (if XY) X by 1, until X reaches Y. If and when X is equal to Y, the program prints “Reached!”

Solution:

    #include<stdio.h>
    int main(){
    int x,y;
    scanf("%d%d",&x,&y);
    if(x==y){
       printf("Reached!\n");
    }
    else if(x<y){
      for(int i=x; i<=y;i++){
        if(i==y){
          printf("Reached!\n");
        }
        else{
          printf("%d, ",i*i); 
        }
      }
    }
    else if(x>y){
      for(int i=x; i>=y;i--){
        if(i==y){
           printf("Reached!\n");
        }
        else{
           printf("%d, ",i*i); 
        }
      } 
    }
    return 0;
    }

Output:

    10 5
    100, 81, 64, 49, 36, Reached!    

Exercise 6:

Write a program (WAP) for the described scenario: Player-1 picks a number X and Player-2 has to guess that number within N tries. For each wrong guess by Player-2, the program prints “Wrong, N-1 Choice(s) Left!” If Player-2 at any time successfully guesses the number, the program prints “Right, Player-2 wins!” and terminates right away. Otherwise after the completion of N wrong tries, the program prints “Player-1 wins!” and halts.

Solution:

    #include<stdio.h>
    int main(){
      int guess,num,time;
      scanf("%d",&num);
      scanf("%d",&time);
      for(int i = 0; i < time; i++) { 
        scanf("%d", &guess);
        if(guess == num) {
            printf("Right, Player-2 wins!\n");
            break;
        } else {
            printf("Wrong, %d Choice(s) Left!\n", time-i-1);
        }
      }
      if(guess != num) {
         printf("Player-1 wins!\n");
      }
    return 0;
    }

Output:

    5
    3
    12 8 5
    Wrong, 2 Choice(s) Left!
    Wrong, 1 Choice(s) Left!
    Right, Player-2 wins!

Exercise 7:

Write a program (WAP) that will run and show keyboard inputs until the user types an 'A' at the keyboard.

Solution:

    #include<stdio.h>
    int main(){
      char input;
      int n=1;
      while (1){
        scanf(" %c", &input);
        if(input == 'A') {
          break;
        }
        printf("Input %d: %c\n", n,input);
        n++;
      }
     return 0;
    }

Output:

  X 
  1
  a
  A
  Input 1: X
  Input 2: 1
  Input 3: a

Exercise 8:

Write a program (WAP) that will reverse the digits of an input integer.

Solution:

    #include<stdio.h>
    int main(){
    int num, reversed_num = 0;
    scanf("%d", &num);
    while (num != 0) {
      int digit = num % 10;
      reversed_num = reversed_num * 10 + digit;
      num /= 10;
    }
    printf("%d\n", reversed_num);
    return 0;
    }

Output:

  1234
  4321

Exercise 9:

Write a program (WAP) that will find the grade of N students. For each student, it will take the marks of his/her the attendance (on 5 marks), assignment (on 10 marks), class test (on 15 marks), midterm (on 50 marks), term final (on 100 marks). Then based on the tables shown below, the program will output his grade.

Solution:

    #include<stdio.h>
    int main() {
      int n, i;
      float A,hw, ct, mt, ft, total_marks, percentage;
      scanf("%d", &n);
      for (i = 1; i <= n; i++) {
          scanf("%f%f%f%f%f", &A,&hw,&ct,&mt,&ft);
          total_marks = (A+hw+ct+mt+ft);
          percentage = (total_marks / 180) * 100;
          if (percentage >= 90) {
              printf("Student %d : A\n",i);
          } else if (percentage >= 86 && percentage <= 89) {
              printf("Student %d : A-\n",i);
          } else if (percentage >= 82 && percentage <= 85) {
              printf("Student %d : B+\n",i);
          } else if (percentage >= 78 && percentage <= 81) {
              printf("Student %d : B\n",i);
          } else if (percentage >= 74 && percentage <= 77) {
              printf("Student %d : B-\n",i);
          } else if (percentage >= 70 && percentage <= 73) {
              printf("Student %d : C+\n",i);
          } else if (percentage >= 66 && percentage <= 69) {
              printf("Student %d : C\n",i);
          } else if (percentage >= 62 && percentage <= 65) {
              printf("Student %d : C-\n",i);
          } else if (percentage >= 58 && percentage <= 61) {
              printf("Student %d : D+\n",i);
          } else if (percentage >= 55 && percentage <= 57) {
              printf("Student %d : D\n",i);
          } else {
              printf("Student %d : F\n",i);
          }
      }
      return 0;
    }

Output:

  2
  5 10 15 44.5 92.5     
  0 7.5 5 20 55.5
  Student 1 : A
  Student 2 : F

Exercise 10:

Write a program (WAP) that will give the sum of first Nth terms for the following series.
1, -2, 3, -4, 5, -6, 7, -8, 9, -10, 11, -12, 13, -14, …….

Solution:

    #include<stdio.h>
    int main() {
    int n, i, sum = 0;
    scanf("%d", &n);
    for (i = 1; i <= n; i++) {
      if (i % 2 == 0) {
          sum -= i;
      } 
      else {
         sum += i;
      }
    }
     printf("Result: %d\n", sum);
     return 0;
    }

Output:

  2
  Result: -1